How To Calculate JEE Main 2019 Marks using Official Answer Keys

Joint Entrance Exam (JEE) Main 2027 ( JEE Main )

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JEE Main 2027 Exam Date Session 1

22 Jan '27 - 24 Jan '27

Updated on Jan 18, 2019 23:57 IST
Here’s how you can calculate JEE Main 2019 marks/score based on official answer keys. Check formula and steps to calculate expected JEE Main 2019 Marks.

JEE Main 2019 official answer keys were released on January 15. NTA, the exam conducting authority, published the official question papers of JEE Main 2019 Paper 1 and Paper 2 along with the recorded responses of candidates on January 14 on the exam website. Contrary to 2018, candidates who appeared for JEE Main 2019, would only be able to view their respective recorded responses along with answer keys of the 90 questions they answered in the exam. Along with the answer keys, the National Testing agency also opened the ‘Answer Key Challenge’ window.

Read: How To Calculate JEE Main 2019 Rank From Percentile

While, there are various tools to help you predict your expected JEE Main rank, there certainly are no tools to help you calculate your JEE Main 2019 score.  In this, article we would do exactly that and tell you how you can calculate JEE Main marks and score based on official answer keys of the exam.

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JEE Main Expected Cutoff

JEE Main Answer Key

JEE Main Question Paper

Read:JEE Main 2019 Topper Interview (January Exam): Dhruv Arora from Indore secures 100 percentile

To calculate JEE Main marks using the official answer keys of JEE Main 2019, aspirants will have to follow the given below steps:

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  1. Download the JEE Main 2019 official answer keys from the website
  2. Compare your recorded responses to the answer keys given by NTA
  3. Refer to the marking scheme of JEE Main 2019 to calculate your expected score
  4. According to JEE Main marking scheme, for every correct response, a candidate will be awarded 4 marks, while 1 mark will be deducted for any question answered incorrectly. No marks will be awarded or deducted for un-attempted questions. All you have to do is apply the formula below:

Formula to calculate expected JEE Main 2019 Marks/Score

(Total number of correct answers X 4) – (Total number of incorrect responses X 1) = Expected score in JEE Main 2019 

5. The total mark calculated would be your probable JEE Main 2019 score.

Note: In JEE Main 2019, each candidate got the same question paper but the sequence of questions were different. Interestingly, the multiple choices/options given against each of the questions were jumbled too. Also, this year, both - the questions as well as the answers/answer key have IDs which was not the case in 2018. So, even though you might have appeared for the exam on the same day and same session as your peer, your answer keys might be completely different. Thus, stick to your own question paper, question IDs and Answer Key IDs. Do not rely or compare your JEE Main question paper to the question papers of other candidates.

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Read:JEE Main 2019 Toppers (Paper 1); 15 Students Secure 100 Percentile

You can also check out JEE Main 2019 official answer keys along with solutions released by various experts below.

JEE Main 2019 Paper Analysis, Answer Key & Solutions by Experts

Coaching Institutes

Link

JEE Main Paper 1 Analysis and Expected Cutoff by FIITJEE

Click here

JEE Main Paper 1 Answer Key & Solutions by Allen Career Institute

Click here

JEE Main Paper 1 Analysis, Answer Key & Solutions by Career Point

Click here

JEE Main Paper 1 Analysis, Answer Key and Solutions by Resonance

Click here

JEE Main 2019 results along with percentile score for Paper 1 has been published by NTA on January 19. With JEE Main overall score and cut-offs yet to be published, candidates have already started predicting their JEE Main ranks and percentile through JEE Main 2019 Rank predictor tools available online. Remember, to determine JEE Main results 2019 and ranklist, NTA will adopt the process of normalization which will based on percentile calculation.

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According to the tentative schedule, JEE Main 2027 counselling registration is likely to commence in June 2027 after the conclusion of both exam sessions.

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The cutoff rank in Round 7 for BTech Computer Science & Engineering under General All India category is 53,013. It is the most competitive branch in the institute.

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Yes, JEE Main is compulsory for admission in B.Tech course at SGSITS.

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After qualifying JEE Main, students need to register themselves for MP BE Counselling, choose colleges/branches, attend rounds and verify documents to secure admission.

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Getting into B.Tech CSE is straightforward. You need to have passed 10+2 with Physics and Mathematics, along with Chemistry, Biotechnology, Biology, or a Technical Vocational subject. Marks from boards like CBSE, ISC, and PSEB are accepted. JEE Main scores are also recognised under the RBUEdge Schol

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Priti Choudhary

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Yes, JEE Main scores are recognised under the RBUEdge Scholarship Program, so your entrance exam effort can also help reduce your fees. A higher score falls in a higher scholarship slab, with the top slab offering a 60% waiver on the course fee. This is a nice reward for the hard work that goes into

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Anya Mehta

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Answered a week ago

The JEE Main Round 7 cutoff 2026 for SGSITS Indore ranged from 53,013 to 90,468 for General All India candidates across BTech branches.

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If a student has appeared for JEE Main, they can apply for B.Tech admission at Galgotias University through the university's admission process. JEE Main scores are considered for preference in the merit list, along with the eligibility requirements of the chosen B.Tech programme. After applying, the

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Suhani Pandey

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For B.Tech admissions, Galgotias University primarily considers eligibility based on Class 12 qualifications and its admission process. JEE Main scores may also be considered for admission, depending on the programme and admission criteria for that year. CUET acceptance can vary by course and admiss

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According to the MSU Baroda CSE Cutoff 2026 for the General AI category, the maximum rank accepted was 900019 in the last round (Round 3).

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