How To Calculate JEE Main 2019 Marks using Official Answer Keys
Joint Entrance Exam (JEE) Main 2026 ( JEE Main )
JEE Main CSAB special counselling
22 Jul '26 - 18 Aug '26
JEE Main 2019 official answer keys were released on January 15. NTA, the exam conducting authority, published the official question papers of JEE Main 2019 Paper 1 and Paper 2 along with the recorded responses of candidates on January 14 on the exam website. Contrary to 2018, candidates who appeared for JEE Main 2019, would only be able to view their respective recorded responses along with answer keys of the 90 questions they answered in the exam. Along with the answer keys, the National Testing agency also opened the ‘Answer Key Challenge’ window.
Read: How To Calculate JEE Main 2019 Rank From Percentile
While, there are various tools to help you predict your expected JEE Main rank, there certainly are no tools to help you calculate your JEE Main 2019 score. In this, article we would do exactly that and tell you how you can calculate JEE Main marks and score based on official answer keys of the exam.
Explore colleges based on JEE Main
Want better recommendations?
There is a 90% more chance of getting best college recommendations by sharing preferences.
- Chat with our counselor
- Get your personalised list of colleges & exams matching your preferences
Read:JEE Main 2019 Topper Interview (January Exam): Dhruv Arora from Indore secures 100 percentile
To calculate JEE Main marks using the official answer keys of JEE Main 2019, aspirants will have to follow the given below steps:
- Download the JEE Main 2019 official answer keys from the website
- Compare your recorded responses to the answer keys given by NTA
- Refer to the marking scheme of JEE Main 2019 to calculate your expected score
- According to JEE Main marking scheme, for every correct response, a candidate will be awarded 4 marks, while 1 mark will be deducted for any question answered incorrectly. No marks will be awarded or deducted for un-attempted questions. All you have to do is apply the formula below:
(Total number of correct answers X 4) – (Total number of incorrect responses X 1) = Expected score in JEE Main 2019
5. The total mark calculated would be your probable JEE Main 2019 score.
Note: In JEE Main 2019, each candidate got the same question paper but the sequence of questions were different. Interestingly, the multiple choices/options given against each of the questions were jumbled too. Also, this year, both - the questions as well as the answers/answer key have IDs which was not the case in 2018. So, even though you might have appeared for the exam on the same day and same session as your peer, your answer keys might be completely different. Thus, stick to your own question paper, question IDs and Answer Key IDs. Do not rely or compare your JEE Main question paper to the question papers of other candidates.
Explore more B.Tech exams with upcoming dates
BITSAT
19 Aug '26
4 Aug '26 - 20 Aug '26
12 Aug '26 - 17 Aug '26
12 Aug '26 - 17 Aug '26
18 Aug '26
18 Aug '26
18 Aug '26
18 Aug '26 - 22 Aug '26
Read:JEE Main 2019 Toppers (Paper 1); 15 Students Secure 100 Percentile
You can also check out JEE Main 2019 official answer keys along with solutions released by various experts below.
| Coaching Institutes |
Link |
| JEE Main Paper 1 Analysis and Expected Cutoff by FIITJEE |
|
| JEE Main Paper 1 Answer Key & Solutions by Allen Career Institute |
|
| JEE Main Paper 1 Analysis, Answer Key & Solutions by Career Point |
|
| JEE Main Paper 1 Analysis, Answer Key and Solutions by Resonance |
JEE Main 2019 results along with percentile score for Paper 1 has been published by NTA on January 19. With JEE Main overall score and cut-offs yet to be published, candidates have already started predicting their JEE Main ranks and percentile through JEE Main 2019 Rank predictor tools available online. Remember, to determine JEE Main results 2019 and ranklist, NTA will adopt the process of normalization which will based on percentile calculation.
Also Read:
- How to challenge JEE Main 2019 answer keys?
- How to calculate JEE Main 2019 Percentile Score - Know Normalization Process
- JEE Main 2019 Paper 1 Analysis, Expected Cutoff & Student Reaction
- Questions asked in JEE Main 2019 Paper 1 and Paper 2 – January Session
- JEE Main 2019 Paper 1 Analysis for Physics, Chemistry and Mathematics
News & Updates
Explore Other Exams
Jun '26 | JoSAA 2026 starts |
1 Jun '26 | JEE Advanced 2026 Result Date |
18 Aug '26 | BITSAT 2026 Iteration-VII Anno... |
21 Aug '26 | BITSAT 2026 Iteration-VII fee ... |
9 Jul '26 | SRMJEEE Phase 3 Result 2026 |
4 Jul '26 - 5 Jul '26 | SRMJEEE 2026 Exam (Phase 3) |
18 Aug '26 | COMEDK 2026 Counselling: Round... |
18 Aug '26 - 21 Aug '26 | COMEDK 2026 Counselling: Round... |
28 Jul '26 | WBJEE 2026 seat allotment - Ro... |
24 Jul '26 - 26 Jul '26 | WBJEE 2026 counselling registr... |
Oct '26 | VITEEE 2027 Registration Start... |
Apr '27 | VITEEE 2027 Mock Test Release ... |
Student Forum
Anything you would want to ask experts?Answered 17 hours ago
Yes, candidates can get scholarship based on performance in JEE (Main) for BTech at NIMS University, Jaipur. Details are given below:
| Scholarship Percentage | JEE Rank |
|---|---|
| 60% Waiver in First Year Tuition Fee | AIR upto 1 Lacs in JEE Mains |
| 50% Waiver in First Year Tuition Fee | AIR between 1 Lacs and 2.25 Lacs in JEE Mains |
| 75% Waiver in First-Year Tuition Fee | Qualified JEE Advance |
S
Contributor-Level 10
Answered 17 hours ago
No, your rank does not change your fees. Merit ranks generated via the JEE Main entrance exam are exclusively used to determine branch selection and seat eligibility during allocation. Once admitted, your tuition fee relies entirely on government social category waivers and annual family income slab
R
Contributor-Level 9
Answered 20 hours ago
With a JEE Main rank of 30,000 (General category, Other State quota), you can secure Mechanical Engineering, Electronics and Instrumentation Engineering, or Civil Engineering at NIT Silchar. Depending on round variations and seat trends, you may also have borderline chances for Electrical Engineerin
R
Contributor-Level 9
Answered 21 hours ago
Students can download the JEE Main syllabus 2027 from the official website of JEE Mains 2027 once released.
M
Contributor-Level 8
Answered 3 days ago
Usually the Cutoffs differ across B.Tech programmes and counselling rounds. However, The Guru Nanak Dev University JEE Main Cutoff 2025 the closing rank of 145410 for round 1 remained the same across the listed B.Tech programmes under the General Home State category, with no variation in closing ran
R
Beginner-Level 5
Answered 3 days ago
For Guru Nanak Dev University JEE Main Cutoff 2025, the listed B.Tech programmes for round 1 had the same closing rank of 145410 under the General Home State category.
The cutoff data displayed above has been sourced from third-party channels. While we strive to ensure accuracy, cutoffs are subject t
R
Beginner-Level 5
Answered 4 days ago
The JEE Main 2025 cutoff closing rank for round 1 at GEU Dehradun for all the listed B.Tech branches was 145410.
The cutoff data displayed above has been sourced from third-party channels. While we strive to ensure accuracy, cutoffs are subject to change and may vary based on category, round, and adm
R
Beginner-Level 5
Answered 4 days ago
GEU Dehradun 2025 cutoff for Round 1 has been released for General Home State category with a closing rank for B.Tech Cse at 145410.
Candidates seeking admission to the B.Tech Cse programme must secure a rank of 145410 or better to be considered for admission.
The cutoff data displayed above has been
R
Beginner-Level 5
Answered 5 days ago
Sorry, but the college does not accept JEE Mains score for admission to BE ECE program at Loyola-ICAM College of Engineering and Technology.
A
Contributor-Level 10
Answered 6 days ago
YES. Galgotias University accepts JEE Main and CUET scores for B.Tech admissions and gives preference to candidates with these scores in the merit list. Students also need to meet the required Class 12 eligibility criteria for their chosen B.Tech program.
V
Beginner-Level 5